An object is at rest at #(8 ,3 ,8 )# and constantly accelerates at a rate of #7/4 m/s^2# as it moves to point B. If point B is at #(6 ,5 ,2 )#, how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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Answer 1 · 2017-12-15T07:40:40

The time is #=2.75s#

The distance #AB# is

#AB=sqrt((6-8)^2+(5-3)^2+(2-8)^2)=sqrt(4+4+36)=(sqrt44)m#

Apply the equation of motion

#s=ut+1/2at^2#

The initial velocity is #u=0ms^-1#

The acceleration is #a=7/4ms^-2#

Therefore,

#sqrt44=0+1/2*7/4*t^2#

#t^2=8/7sqrt44#

#t=sqrt(8/7sqrt44)=2.75s#