An object is thrown vertically from a height of #2 m# at #21 m/s#. How long will it take for the object to hit the ground?

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Answer 1 · 2018-03-06T02:21:13

#0.092 s#

Let's find the velocity with which it will hit the ground,applying

#v^2=u^2 +2gs#

Given, #u=21ms^-1,s=2m#

So, #v^2=21×21 +2×9.8×2#

So, #v=21.92ms^-1#

Now,if it took time #t# in gaining that much velocity we can use, #v=u+g t#

So, #21.92=21 + 9.8t#

Or, #t=0.092 s#