At a construction site a pipe wrench struck the ground with a speed of 24m/s. (a) From what height was it inadvertently dropped? (b) How long was it falling?

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Answer 1 · 2015-12-07T22:55:40

$(a)$

$29.4"m"$

$(b)$

$2.45"s"$

$(a)$

$v^2=u^2+2as$

This becomes:

$24^2=0+2xx9.8xxs$

$:.s=(576)/(2xx9.8)=29.4"m"$

$(b)$

$s=1/2"g"t^2$

$:.t=sqrt((2s)/(g)$

$:.t=sqrt((2xx29.4)/(9.8))=2.45"s"$