$\frac{b}{(b + 4) (b - 4)} + \frac{10}{(b - 9) (b + 4)}$ $b/((b+4)(b-4)) + 10/((b-9)(b+4))$ its asking me to add these fractions by finding the LCD and I need help ?

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$\frac{b}{(b + 4) (b - 4)} + \frac{10}{(b - 9) (b + 4)}$ $b/((b+4)(b-4)) + 10/((b-9)(b+4))$ its asking me to add these fractions by finding the LCD and I need help ?

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Answer 1 · 2017-02-21T17:07:17

See below.

Explanation:

$\frac{b}{(b + 4) (b - 4)} + \frac{10}{(b - 9) (b + 4)}$ $b/((b+4)(b-4) )+ 10/((b-9)(b+4) )$

Both denominator have the factors $(b + 4) (b - 4) (b - 9)$ $(b+4)(b-4)(b-9)$ so

multiplying and dividing both fractions for it we have

$\frac{1}{(b + 4) (b - 4) (b - 9)} (\frac{b (b + 4) (b - 4) (b - 9)}{(b + 4) (b - 4)} + \frac{10 (b + 4) (b - 4) (b - 9)}{(b - 9) (b + 4)}) = \frac{b (b - 9) + 10 (b + 4)}{(b + 4) (b - 4) (b - 9)}$ $1/((b+4)(b-4)(b-9))((b(b+4)(b-4)(b-9))/((b+4)(b-4) )+(10 (b+4)(b-4)(b-9))/((b-9)(b+4) ))=(b(b-9)+10(b+4))/((b+4)(b-4)(b-9))$

and finally

$\frac{b}{(b + 4) (b - 4)} + \frac{10}{(b - 9) (b + 4)} = \frac{b^{2} + b + 40}{(b + 4) (b - 4) (b - 9)}$ $b/((b+4)(b-4) )+ 10/((b-9)(b+4) )=(b^2+b+40)/((b+4)(b-4)(b-9))$

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$\frac{b}{(b + 4) (b - 4)} + \frac{10}{(b - 9) (b + 4)}$ $b/((b+4)(b-4)) + 10/((b-9)(b+4))$ its asking me to add these fractions by finding the LCD and I need help ?

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Explanation:

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b/((b+4)(b-4)) + 10/((b-9)(b+4))b(b+4)(b−4)+10(b−9)(b+4)b/((b+4)(b-4)) + 10/((b-9)(b+4)) its asking me to add these fractions by finding the LCD and I need help ?

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Explanation:

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Impact of this question

$\frac{b}{(b + 4) (b - 4)} + \frac{10}{(b - 9) (b + 4)}$ $b/((b+4)(b-4)) + 10/((b-9)(b+4))$ its asking me to add these fractions by finding the LCD and I need help ?