Can $y = 2 x^{2} + 2 x - 8$ $y=2x^2 +2x-8$ be factored? If so what are the factors ?

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Can $y = 2 x^{2} + 2 x - 8$ $y=2x^2 +2x-8$ be factored? If so what are the factors ?

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Answer 1 · 2015-12-31T21:07:31

It is non factorable

Explanation:

2( $x^{2}$ $x^2$ + x - 4)

At this point, it is obvious that it is non factorable since there are no two integers that multiply to -4 and that add to + 1. All you can do to factor it is extract a common factor like shown above.

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Can $y = 2 x^{2} + 2 x - 8$ $y=2x^2 +2x-8$ be factored? If so what are the factors ?

1 Answer

Explanation:

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Can $y = 2 x^{2} + 2 x - 8$ $y=2x^2 +2x-8$ be factored? If so what are the factors ?