Can $y = 3 x^{2} - 39 x - 90$ $y=3x^2-39x-90$ be factored? If so what are the factors ?

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Can $y = 3 x^{2} - 39 x - 90$ $y=3x^2-39x-90$ be factored? If so what are the factors ?

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Answer 1 · 2015-12-16T00:13:50

Factor y = 3x^2 - 39x - 90

Ans: y = (x +2)(x -15)

Explanation:

I use the new AC Method to factor trinomials (Socratic Search)
$y = 3 Y = 3 (x^{2} - 13 x - 30)$ $y = 3Y = 3(x^2 - 13x - 30)$ . Factor $Y = x^{2} - 13 x - 30)$ $Y = x^2 - 13x - 30)$ .
Find 2 numbers knowing sum (b = -13) and product (c = -30)
Factor pairs of (-30) --> (-2, 15). This sum is 13 = -b. Then the opposite sum gives 2 numbers: 2 and - 15.

Factored form: $y = 3 (x + 2) (x - 15) =$ $y = 3(x + 2)(x - 15) =$

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Can $y = 3 x^{2} - 39 x - 90$ $y=3x^2-39x-90$ be factored? If so what are the factors ?

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Explanation:

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Science

Math

Humanities

... and beyond

Can y=3x2−39x−90y=3x^2-39x-90 be factored? If so what are the factors ?

1 Answer

Explanation:

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Can $y = 3 x^{2} - 39 x - 90$ $y=3x^2-39x-90$ be factored? If so what are the factors ?