Can $y = x^{2} + 10 x + 21$ $y=x^2 + 10x + 21$ be factored? If so what are the factors ?

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Can $y = x^{2} + 10 x + 21$ $y=x^2 + 10x + 21$ be factored? If so what are the factors ?

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Answer 1 · 2015-12-13T19:50:12

Yes.

Explanation:

Yes.

$\times y = x^{2} + 10 x + 21 \Leftrightarrow y = (x + 3) (x + 7)$ $color(white)(xx)y=x^2+10x+21<=>y=(x+3)(x+7)$

Answer 2 · 2015-12-13T19:52:24

$(x + 3) (x + 7)$ $(x+3)(x+7)$

Explanation:

To look for the factored form of a polynomial, look for the numbers whose product is the final number and whose sum is the middle constant.

The possible pairs of numbers whose product is $21$ $21$ are:

$1, 21$ $1,21$

$3, 7$ $3,7$

The sum of $3$ $3$ and $7$ $7$ are $10$ $10$ , which is the middle term of the polynomial.

Thus, we can factor $x^{2} + 10 x + 21$ $x^2+10x+21$ into $(x + 3) (x + 7)$ $(x+3)(x+7)$ .

A good way to check your work is to redistribute the factored form.

$(x + 3) (x + 7) = x^{2} + 7 x + 3 x + 21 = x^{2} + 10 x + 21$ $(x+3)(x+7)=x^2+7x+3x+21=x^2+10x+21$

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Can $y = x^{2} + 10 x + 21$ $y=x^2 + 10x + 21$ be factored? If so what are the factors ?

2 Answers

Explanation:

Explanation:

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Can $y = x^{2} + 10 x + 21$ $y=x^2 + 10x + 21$ be factored? If so what are the factors ?