Question

Consider the function `f(x) = sqrtx` on the interval [0, 4], how do you find the average or mean slope of the function on this interval?

Answer 1

1/2

Explanation:

Mean slope in an interval ( a, b)

`= (int y'dx)`/(length of the interval)

`=(int dy)/(b-a)`

`=(y(b)-y(a))/(b-a)`. And here, it is

`sqrt4/4=1/2`.