Consider the line y=8x-2y=8x−2. What is the equation of the line that is parallel to this line and passes through the point (-5,6)?

1 Answer
Zor Shekhtman
Nov 26, 2015

y=8x+46y=8x+46

Explanation:

All lines with the same slope are parallel to each other.

All lines with a slope 88 have equation
y=8x+Cy=8x+C
where CC is some constant.

Let's find a constant CC such that point (-5,6)(−5,6) lies on a line:
6 = 8(-5)+C6=8(−5)+C
from which follows:
C = 46C=46

Therefore, line y=8x+46y=8x+46 is parallel to a given line y=8x-2y=8x−2 and passes through point (-5,6)(−5,6).

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