What is the equation of a line that satisfies the given conditions: perpendicular to $y = - 2 x + 5$ $y= -2x + 5$ and passing through (4, -10)?

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Answer 1 · 2015-11-19T16:41:19

$y = 0.5 x - 12$ $y=0.5x-12$

Since the line must be perpendicular, the slope $m$ $m$ should be the opposite and inverse of the one in your original function.

$m = - (- \frac{1}{2}) = \frac{1}{2} = 0.5$ $m=-(-1/2)=1/2=0.5$

Now all you have to do is use the point slope equation:

Given coordinate: $(4, - 10)$ $(4,-10)$

$y - y_{0} = m (x - x_{0})$ $y-y_0=m(x-x_0)$

$y - (- 10) = 0.5 (x - 4)$ $y-(-10)=0.5(x-4)$

$y + 10 = 0.5 x - 2$ $y+10=0.5x-2$

$y = 0.5 x - 2 - 10$ $y=0.5x-2-10$

$y = 0.5 x - 12$ $y=0.5x-12$

What is the equation of a line that satisfies the given conditions: perpendicular to y= -2x + 5y=−2x+5y= -2x + 5 and passing through (4, -10)?