Determine the wavelength, in nanometers, of the line in the Balmer series corresponding to #n_2# = 5? Express your answer using five significant figures.

Information given

"Use the Balmer equation

#nu = 3.2881 xx10^(15)"s"^(−1) * (1/2^2−1/n^2)#

to answer following questions."

Correct answer

#lambda=434.16# nm

What I got

I got # ~~ 434.47# nm

1 Answer
Nov 14, 2016

#lamda = "434.17 nm"#

Explanation:

This is pretty much a plug-n-play problem in which all you have to do is plug in the value for #n_2# in the given equation.

The problem provides you with the equation

#color(blue)(ul(color(black)(nu = 3.2881 * 10^(15)"s"^(-1) * (1/2^2 - 1/n_2^2))))#

The first thing to do here is to rearrange this equation to work with wavelength, #lamda#. As you know, frequency and wavelength have an inverse relationship described by the equation

#color(blue)(ul(color(black)(lamda * nu = c)))#

Here

#c# - the speed of light in a vacuum, equal to #"299,792,458 m s"^(-1)#

This means that you have

#nu = c/(lamda)#

Plug this into the Balmer equation to get

#c/(lamda) = 3.2881 * 10^(15)"s"^(-1) * (1/4 - 1/(n_2^2))#

#lamda = c/(3.2881 * 10^(15)"s"^(-1) * (1/4 - 1/(n_2^2)))#

Plug in your values to find

#lamda = ("299,792,458 m" color(red)(cancel(color(black)("s"^(-1)))))/(3.2881 * 10^(15) color(red)(cancel(color(black)("s"^(-1)))) * (1/4 - 1/25))#

#lamda = 4.341666 * 10^(-7)"m"#

Expressed in nanometers and rounded to five sig figs, the answer will be

#color(darkgreen)(ul(color(black)(lamda = 434.17 * 10^(-9)"m" = "434.17 nm"))) -># close enough