Does #sum_1^oo [3/n(n+4)] - [(2^(2n)/7^n+1)]# converge? Calculus Tests of Convergence / Divergence Integral Test for Convergence of an Infinite Series 1 Answer A. S. Adikesavan Sep 30, 2016 Diverges. Explanation: Rearranging, the infinite seris is #sum (3 -1) + 12 sum 1/n -sum (4/7)^n# #=oo+oo -ln(1-4/7)# #=oo# Answer link Related questions What is the Integral Test for Convergence of an Infinite Series? How do you know when to use the integral test for an infinite series? How do you use the Integral test on the infinite series #sum_(n=1)^oo1/root5(n)# ? How do you use the Integral test on the infinite series #sum_(n=1)^oo1/n^5# ? How do you use the Integral test on the infinite series #sum_(n=1)^oo1/(2n+1)^3# ? How do you use the Integral test on the infinite series #sum_(n=1)^oo1/sqrt(n+4)# ? How do you determine if the series #ln(1/2) + ln(1/3) + ln(3/4) + ... +ln[k/(k + 1)] + ....# converges? How do you know #{-1,1,-1,1,-1,1,...}# converges or diverges? Using the integral test, how do you show whether # (1 + (1/x))^x# diverges or converges? Using the integral test, how do you show whether #sum 1/(n^2+1)# diverges or converges from n=1... See all questions in Integral Test for Convergence of an Infinite Series Impact of this question 1450 views around the world You can reuse this answer Creative Commons License