Earth's oceans have an average depth of 3800 m, a total area of $3.63 x 10^{8} k m^{2}$ $3.63 x 10^8 km^2$ , and an average concentration of dissolved gold of $5.8 x 10^{- 9}$ $5.8 x 10^-9$ $g$ $g$ / $L$ $L$ . How many grams of gold are in the oceans?

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Earth's oceans have an average depth of 3800 m, a total area of $3.63 x 10^{8} k m^{2}$ $3.63 x 10^8 km^2$ , and an average concentration of dissolved gold of $5.8 x 10^{- 9}$ $5.8 x 10^-9$ $g$ $g$ / $L$ $L$ . How many grams of gold are in the oceans?

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Answer 1 · 2016-09-05T08:43:55

Over 8 million kilograms; i.e. $8 \times 10^{9} \cdot g$ $8xx10^9*g$

Explanation:

We need to find the volume of the ocean in $m^{3}$ $m^3$ , and then multiply this volume by the average concentration in $g \cdot L^{- 1}$ $g*L^-1$ knowing that there are $1000 \cdot L$ $1000 *L$ in a $m^{3}$ $m^3$ .

$Volume of the oceans$ $"Volume of the oceans"$ $=$ $=$ $3.63 \times 10^{11} \cdot m^{2} \times 3800 \cdot m$ $3.63xx10^11*m^2xx3800*m$ $=$ $=$ $1.38 \times 10^{15} \cdot m^{3}$ $1.38xx10^15*m^3$ .

$Mass of gold$ $"Mass of gold"$ $=$ $=$ $Volume \times concentration$ $"Volume "xx" concentration"$

$=$ $=$ $1.38xx10^15*cancel(m^3)xx5.8xx10^-9*g*cancel(L^-1)xx1000*cancelL*cancel(m^-3)$

$=$ $8004000000$ $g$

$=$ $8004000*kg$

Anyway, go over my figures carefully. There is a lot of arithmetic here.

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Earth's oceans have an average depth of 3800 m, a total area of $3.63 x 10^{8} k m^{2}$ $3.63 x 10^8 km^2$ , and an average concentration of dissolved gold of $5.8 x 10^{- 9}$ $5.8 x 10^-9$ $g$ $g$ / $L$ $L$ . How many grams of gold are in the oceans?

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Explanation:

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Earth's oceans have an average depth of 3800 m, a total area of 3.63 x 10^8 km^23.63x108km23.63 x 10^8 km^2, and an average concentration of dissolved gold of 5.8 x 10^-95.8x10−95.8 x 10^-9 ggg/LLL. How many grams of gold are in the oceans?

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Explanation:

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Earth's oceans have an average depth of 3800 m, a total area of $3.63 x 10^{8} k m^{2}$ $3.63 x 10^8 km^2$ , and an average concentration of dissolved gold of $5.8 x 10^{- 9}$ $5.8 x 10^-9$ $g$ $g$ / $L$ $L$ . How many grams of gold are in the oceans?