Find the derivative of #1/(-sint)#?

Question

I've taken the negative sign out to get #-(1/\sint)'# but that's as far as I got...

I wanted to apply the product rule instead of the quotient rule.
(Symbolab uses the quotient rule)

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Answer 1 · 2018-05-28T18:22:11

#cot(t)csc(t)#

Before starting we know that
#-1/sint=-csct#

Also

#-d/dtcsct=-(-cot(t)csc(t))#

#=cot(t)csc(t)#