For the experiment of tossing a coin three times, how do you find the probability of getting at least one head?

1 Answer
Apr 26, 2017

7/8.78.

Explanation:

The Sample Space S,S, associated with the Experiment of

tossing a coin thrice is,

S={(H,H,H),(H,H,T),(H,T,H),(H,T,T),(T,H,H),(T,H,T),(T,T,H),(T,T,T)}.S={(H,H,H),(H,H,T),(H,T,H),(H,T,T),(T,H,H),(T,H,T),(T,T,H),(T,T,T)}.

:. n(S)=8.

E=the Event getting at least one Head

=the Event getting no. of Heads 1, or, 2, or 3

:. E={(H,H,H),(H,H,T),(H,T,H),(H,T,T),(T,H,H),(T,H,T),(T,T,H)}.

:. n(E)=7.

:. P(E)=(n(E))/(n(S))=7/8.

As an Aliter, we note that,

E'=the Complementary Event of the Event E

=the Event getting not a single Head at all

:. E'={(T,T,T)} rArr P(E')=1/8.

:. P(E)=1-P(E')=1-1/8=7/8.

Enjoy Maths.!