Question

For the experiment of tossing a coin three times, how do you find the probability of getting at least two heads?

Answer 1

`1/2`

Explanation:

Since we only have three throws it will be easier to list all possibilities, of 1st, 2nd and 3rd throws

`H =` head

`T=`Tail

`color(blue)(HHH)`

`color(blue)(HHT)`
`color(blue)(HTH)`
`color(blue)(THH)`

`T T H`
`THT`
`H T T`

`T T T`

Eight possibilities in all, and the requirement of at least two heads is shown in blue

`X=" number of heads"`

`P(X >=2)=4/8=1/2`

Answer 2

1/2

Explanation:

total possible case :- HHH, HHT, HTH, THH, TTT, TTH, THT, HTT

At least two heads :- 4

so the probability of getting at least two head is 4/8 = 1/2