Question

For the experiment of tossing a six sided die twice, what is the probability that the sum is 2, 3 or 12?

Answer 1

`P(2,3,12) = 4/36 = 1/9`

Explanation:

If you toss the die twice, there are `6xx6 = 36` different outcomes.
Each of the `6` numbers for the first throw can be combined with each of the same six for the second throw.

Of those `36` outcomes, we only want:

a total of `2" "rarr` this can only come from `1+1=2`
a total of `3" "rarr` this can come from `1+2=3 or 2+1=3`
a total of `12" "rarr` this can only come from `6+6=12`

So, of the total of `36` possible outcomes, there are only `4` that we want.

`P(2,3,12) = 4/36 = 1/9`