Question

For the experiment of tossing a six sided die twice, what is the probability that the sum is odd and no more than 7?

Answer 1

See a solution process below:

Explanation:

From this chart you can see there are a possible of `36` outcomes from tossing the die twice:

Out of these there are `12` outcomes which are odd and not greater than `7`:

Therefore the Probability is:

`12/36 = 1/3` or `1 " in " 3` or `33.3%`