For the experiment of tossing a six sided die twice, what is the probability that the sum is odd and no more than 7?

1 Answer
smendyka
Jan 12, 2018

See a solution process below:

Explanation:

From this chart you can see there are a possible of 3636 outcomes from tossing the die twice:

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Out of these there are 1212 outcomes which are odd and not greater than 77:

Therefore the Probability is:

12/36 = 1/31236=13 or 1 " in " 31 in 3 or 33.3%33.3%

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