George studied 3/4 hour on Monday and 7/8 hour on Tuesday. How long did he study altogether on both days?

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George studied 3/4 hour on Monday and 7/8 hour on Tuesday. How long did he study altogether on both days?

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Answer 1 · 2016-12-15T18:41:11

$\frac{13}{8}$ $13/8$ hours or $1 \frac{5}{8}$ $1 5/8$ hours.

Explanation:

To determine how much total time George studied must solve

$\frac{3}{4} + \frac{7}{8}$ $3/4 + 7/8$

To do this we must multiply the first fraction by the appropriate form of $1$ $1$ to get these two fractions over a common denominator, in this case $8$ $8$ :

$(\frac{2}{2} \times \frac{3}{4}) + \frac{7}{8} \to$ $(2/2 xx 3/4) + 7/8 ->$

$(\frac{2 \times 3}{2 \times 4}) + \frac{7}{8} \to$ $((2 xx 3)/(2 xx 4)) + 7/8 ->$

$\frac{6}{8} + \frac{7}{8}$ $6/8 + 7/8$

We can now add these two fractions because they are over a common denominator:

$\frac{6 + 7}{8}$ $(6 + 7)/8$

$\frac{13}{8}$ $13/8$

or

$\frac{8 + 5}{8} \to$ $(8 + 5)/8 ->$

$\frac{8}{8} + \frac{5}{8}$ $8/8 + 5/8$

$1 \frac{+}{58}$ $1 + /58$

$1 \frac{5}{8}$ $1 5/8$

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George studied 3/4 hour on Monday and 7/8 hour on Tuesday. How long did he study altogether on both days?

1 Answer

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