Given: 1.65 L of water added to 112 grams of sodium acetate ( $N a C_{2} H_{3} O_{2}$ $NaC_2H_3O_2$ ). What is the concentration of the solution?

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Answer 1 · 2016-07-06T18:12:57

$Concentration$ $"Concentration"$ $=$ $=$ $\frac{Moles of solute}{Volume of solution}$ $"Moles of solute"/"Volume of solution"$

$Concentration$ $"Concentration"$ $=$ $=$ $(112*cancelg)/(82.03*cancelg*mol^-1)xx1/(1.65*L)$ $=$ $0.828*mol*L^-1" with respect to sodium acetate"$ .

We have assumed (reasonably) that volume would remain constant after dissolution.

Would the $pH$ of this solution be greater or less than $7$ ; why?

Given: 1.65 L of water added to 112 grams of sodium acetate (NaC_2H_3O_2NaC2H3O2NaC_2H_3O_2). What is the concentration of the solution?