Given: 1.65 L of water added to 112 grams of sodium acetate (NaC_2H_3O_2). What is the concentration of the solution?

1 Answer
Jul 6, 2016

"Concentration" = "Moles of solute"/"Volume of solution"

Explanation:

"Concentration" = (112*cancelg)/(82.03*cancelg*mol^-1)xx1/(1.65*L) = 0.828*mol*L^-1" with respect to sodium acetate".

We have assumed (reasonably) that volume would remain constant after dissolution.

Would the pH of this solution be greater or less than 7; why?