Given an aqueous solution in which the $[H^+]=5.0*10^-3$ $M$ , what is the molar hydroxide ion concentration?

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Answer 1 · 2017-02-20T17:10:31

$[HO^-]=10^(-11.7)=2.0xx10^-12*mol*L^-1$

The easiest way to approach this problem is to use logarithms, and use the relationship:

$pH + pOH=14$

This is specified for aqueous solution under standard conditions.

So $[H_3O^+]=5xx10^-3*mol*L^-1$ , and thus,

$pH=-log_10(5xx10^-3)=2.30$

And thus $pOH=11.70$ ,

and thus $[HO^-]=10^(-11.7)=2.0xx10^-12*mol*L^-1$

Given an aqueous solution in which the [H^+]=5.0*10^-3[H^+]=5.0*10^-3 MM, what is the molar hydroxide ion concentration?