Question

Given `log_b 2= 0.3562`, `log_b 3=0.5646`, and `log_b 5=0.8271`, how do you evaluate `log_b(5/3)`?

Answer 1

`0.2625`

Explanation:

Use `log_b (m/n) =log_b m-log_b n`

Here, `log_b(5/3)=log_b 5-log_b 3=0.8271-0.5646=0.2635`.