Question

Given `log_b3= 0.5283` and `log_b5=0.7740`, how do you find `log_b(5/3)`?

Answer 1

`log_b(5/3) = 0.2457`

Explanation:

Remember that `log_b(x/y) = log_bx -log_by`

So

`log_b(5/3) = log_b5 – log_b3 = 0.7740 - 0.5283`

`log_b(5/3) = 0.2457`