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Given the probability p=0.36 that an event will happen, how do you find the probability that the event will not happen?

1 Answer

Oct 2, 2017

$Probability (! p) = 0.64$ $"Probability"(!p)=0.64$

Explanation:

An event must either occur or not occur. That is either $p$ $p$ or not $p$ $p$ is certain.

The probability of certainty is $100 % = 1$ $100%=1$

If $Probability (p) = 0.36$ $"Probability"(p)=0.36$
then
$XXX Probability (p) + Probability (! p) = 1 xxxx$ $color(white)("XXX")"Probability"(p)+"Probability"(!p)=1color(white)("xxxx")$ where $! p$ $!p$ is used to denote "not " $p$ $p$

$XXX 0.36 + Probability (! p) = 1$ $color(white)("XXX")0.36+"Probability"(!p)=1$

$XXX Probability (! p) = 1 - 0.36 = 0.64$ $color(white)("XXX")"Probability"(!p)=1-0.36=0.64$

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