Question

How can you evaluate `((2x-5)(x-y)) / ((y-x)(3x-1))`?

Answer 1

`-(2x-5)/(3x-1)`

Explanation:

First note that:
`((2x-5)(x-y))/((y-x)(3x-1))=-((2x-5)cancel((x-y)))/(cancel((x-y))(3x-1))`

So in fact this expression is only a function of `x` and the value of `y` is irrelevant. Plug the value of `x` into the remaining expression to evaluate it, for example `x=1`:

`-(2x-5)/(3x-1)=-(2-5)/(3-1)=-(-3)/(2)=3/2`