How can you evaluate $3/(x+4)-1/(x+6)$ ?

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Answer 1 · 2018-05-29T12:19:26

$3/(x+4)-1/(x+6)$

Establishing a common denominator (times both the numerator and denominator by $(x+4)(x+6)$

= $(3(x+6))/((x+4)(x+6))-(x+4)/((x+4)(x+6))$

Simplifying the equation by expanding the brackets
= $(3x+18-x-4)/((x+4)(x+6))$

Simplifying to its simplest form
= $(2x+14)/((x+4)(x+6))$

Answer 2 · 2018-05-29T12:27:45

$color(brown)(=> (2(x+7)) / (x^2 + 10x + 24)$ or $color(blue)((2(x+7)) / ((x+4) (x+6))$

Evaluate $3/(x+4) - 1/(x+6)$

L C M for $(x+4), (x+6)$ is $(x+4)*(x+6)$

$=> (3 * (x+6) - (x+4)) / ((x+4)*(x+6))$

$=> (3x + 18 - x - 4) / ((x+4) * (x+6))$

$color(brown)(=> (2(x+7)) / (x^2 + 10x + 24)$

How can you evaluate 3/(x+4)-1/(x+6)3/(x+4)-1/(x+6)?