How do find the derivative of $y= (1- sec x)/ tan x$ ?

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Answer 1 · 2018-07-30T18:53:04

$(dy)/(dx)=cscx(cotx-cscx)$

Here ,

$y=(1-secx)/tanx$

$=>y=1/tanx-secx/tanx$

$=>y=cotx-(1/cosx)/(sinx/cosx)$

$=>y=cotx-cscx$

$(dy)/(dx)=-csc^2x-(-cscxcotx)$

$(dy)/(dx)=-csc^2x+cscxcotx$

$:.(dy)/(dx)=cscx(cotx-cscx)$

How do find the derivative of y= (1- sec x)/ tan xy= (1- sec x)/ tan x?