How do find the derivative of y = x^2 sinx?

1 Answer
Aug 5, 2015

dy/dx = 2xsin(x) + x^2cos(x)

Explanation:

You can use the product rule to find the derivative. The product rule says the following:

If h(x) = f(x)g(x), then h'(x) = f'(x)g(x) + f(x)g'(x)

In our case,

h(x) = x^2sinx

f(x) = x^2

g(x) = sinx

f'(x) = 2x

g'(x) = cosx

Plug in those values into our definition for the product rule to get

dy/dx = h'(x) = 2xsin(x) + x^2cos(x)