How do find the quotient of $(x^{2} - 3 x + 2) \div (x - 1)$ $(x^2-3x+2) div (x-1)$ ?

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How do find the quotient of $(x^{2} - 3 x + 2) \div (x - 1)$ $(x^2-3x+2) div (x-1)$ ?

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Answer 1 · 2015-10-27T14:08:20

$x - 2$ $x-2$

Explanation:

$(x^{2} - 3 x + 2) \div (x - 1)$ $(x^2-3x+2) -: (x-1)$
$= (x^{2} - x - 2 x + 2) \div (x - 1)$ $=(x^2-x-2x+2)-: (x-1)$
$= (x (x - 1) - 2 (x - 1)) \div (x - 1)$ $=(x(x-1)-2(x-1))-: (x-1)$
$= (x - 1) (x - 2) \div (x - 1)$ $=(x-1)(x-2)-: (x-1)$
$= x - 2$ $=x-2$

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How do find the quotient of $(x^{2} - 3 x + 2) \div (x - 1)$ $(x^2-3x+2) div (x-1)$ ?

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How do find the quotient of (x^2-3x+2) div (x-1)(x2−3x+2)÷(x−1)(x^2-3x+2) div (x-1)?

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How do find the quotient of $(x^{2} - 3 x + 2) \div (x - 1)$ $(x^2-3x+2) div (x-1)$ ?