Question

How do I find the binomial expansion of `(1+12x)^(3/4)`?

Answer 1

Use the general formula

`(1+X)^\alpha = \sum_{n=0}^\infty (alpha(alpha-1)(alpha -2) ... (alpha -n +1))/(n!) X^n`

`(1+X)^\alpha = 1 + alpha X + (alpha (alpha -1))/2 X^2 + (alpha (alpha -1)(alpha-3))/6 X^3 + ...`

with `alpha = 3/4` and `X = 12x`.