How do I find the length of the cardioid r=1+sintheta? Precalculus Polar Coordinates Cardioid Curves 1 Answer Konstantinos Michailidis Nov 7, 2015 The length of the cardiod r=1+sintheta between a and b is L= int_a^b (sqrt(r^2+((dr)/(d(theta)))^2))(d(theta)) hence dr/(d(theta))=costheta and L=int_a^b (sqrt(1+sin^2theta+2costheta+cos^2theta))d(theta)=> L=sqrt2*int_a^b sqrt(1+costheta)d(theta)=> L=sqrt2[(2sqrt(1+costheta))*tan(theta/2)]_a^b=> L=2sqrt2[sqrt(1+cosb)*cos(b/2)-sqrt(1+cosa)*cos(a/2)] Answer link Related questions What is a cardioid curve? What is the graph of r = a ± a cos θ? What is the graph of r = 2a(1 + cosθ)? What is the graph of the Cartesian equation (x^2 + y^2 - 2ax)^2 = 4a^2(x^2 + y^2)? What is the graph of r = sin^2(π/8 - θ/4)? What is the graph of the Cartesian equation y = 0.75 x^(2/3) +- sqrt(1 - x^2)? How do I find the area inside a cardioid? How do I find the area inside the cardioid r=1+costheta? How do I find the length of the cardioid r=1+costheta? How do I graph cardioid r = 2 + 2cosθ? See all questions in Cardioid Curves Impact of this question 7720 views around the world You can reuse this answer Creative Commons License