How do I find the vertex of $y = {(x + 2)}^{2} - 3$ $y=(x+2)^2-3$ ?

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Answer 1 · 2015-07-29T19:54:06

The vertex is at $(- 2, - 3)$ $color(red)((-2,-3)$ .

$y = {(x + 2)}^{2} - 3$ $y = (x +2)^2-3$

The vertex form for the equation of a parabola is

$y = a {(x - h)}^{2} + k$ $y = a(x-h)^2 + k$ , where ( $h, k$ $h, k$ ) is the vertex of the parabola.

Your equation is already in vertex form

By comparing the two equations, we see that $h = - 2$ $h = -2$ and $k = - 3$ $k = -3$ .

The vertex is at ( $- 2, - 3$ $-2,-3$ ).

Graph

How do I find the vertex of y=(x+2)^2-3y=(x+2)2−3y=(x+2)^2-3?