How do I find the vertex of y=(x+7)^2y=(x+7)2?

1 Answer
Elizabeth P.
Oct 26, 2014

The equation is in vertex form (y = a(x-h)^2 + ky=a(x−h)2+k) where the vertex is (h, k). Since the original form has you subtracting h, h more than likely has an opposite sign then what is in the equation. In the example, 7 is being added so therefore h = - 7. Since nothing is being added to the equation, k = 0. Therefore the vertex of y = (x +7)^2y=(x+7)2 is (-7, 0)(−7,0).

Here are some other examples to help you:

y = -2 (x - 4)^2 - 3y=−2(x−4)2−3 has h = 4 and k= -3, so the vertex is (4,-3)(4,−3).

y = 4(x + 1)^2 + 5y=4(x+1)2+5 has h = -1 and k = 5, so the vertex is (-1,5)(−1,5).

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