How do I multiply the matrix #((3, 0, -19),(0, 7, 1), (1, 1/5, 2/3))# by -6?

1 Answer
Sep 13, 2014

You would do this by multiplying every single component of that matrix by -6. Let's say that you had the matrix:

#((a,b),(c,d))# multiplied by some constant #k#. You would then have:

#k ((a,b),(c,d))#=#((ka,kb),(kc,kd))#

So in your case, with k=-6 and #*# denoting multiplication, and we have:

#-6((3,0,-19),(0,7,1),(1,1/5,2/3))=((-6*3,-6*0,-6*-19),(-6*0,-6*7,-6*1),(-6*1,-6*1/5,-6*2/3))=((-18,0,114),(0,-42,-6),(-6,-6/5,-4))#