How do you add #(49x-2)+(4x^2+x+7)#?

1 Answer
Mar 19, 2018

#4x^2 + 50x + 5#

Explanation:

Add
#(49x−2)+(4x2+x+7)#

1) Clear the parentheses by distributing the coefficients.

In this case, both parentheses have coefficients of #1#, which are not written because they are understood.

After you have cleared the parentheses by multiplying all the terms inside each set of parentheses by #1#, you get this:
#49x - 2 + 4x^2 + x + 7#

2) Group like terms
#4x^2    + 49x + x       -2 + 7#

3) Combine like terms
#4x^2 + 50x + 5# #larr# answer