How do you add or subtract $\frac{4 x + y}{2 x + 3 y} - \frac{2 x - 2 y}{2 x + 3 y}$ $(4x+y)/(2x+3y)-(2x-2y)/(2x+3y)$ ?

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Answer 1 · 2015-05-22T07:30:49

$\frac{4 x + y}{2 x + 3 y} - \frac{2 x - 2 y}{2 x + 3 y}$ $(4x+y)/(2x+3y)-(2x-2y)/(2x+3y)$

here the denominator is same so we can rewrite the expression as:
$\frac{(4 x + y) - (2 x - 2 y)}{2 x + 3 y}$ $((4x+y)-(2x-2y))/(2x+3y)$

$= \frac{4 x + y - 2 x + 2 y}{2 x + 3 y}$ $= (4x+y- 2x +2y)/(2x+3y)$
$=cancel (2x +3y)/cancel(2x+3y)$
$=1$

How do you add or subtract (4x+y)/(2x+3y)-(2x-2y)/(2x+3y)4x+y2x+3y−2x−2y2x+3y(4x+y)/(2x+3y)-(2x-2y)/(2x+3y)?