How do you add #(x^2 + 3x+5) + (x^2 + 4x + 1) #?

1 Answer
Alan P. · Konstantinos Michailidis
Sep 9, 2015

#(x^2+3x+5)+(x^2+4x+1)#
#color(white)("XXX")=2x^2+7x+6#

Explanation:

Well you can do it like this
#(color(red)(x^2)+color(red)(3x)+color(red)(5))+(color(blue)(x^2)+color(blue)(4x)+color(blue)(1))#

#color(white)("XXX")=(color(red)(x^2)+color(blue)(x^2))+(color(red)(3x)+color(blue)(4x))+(color(red)(5)+color(blue)(1))#

#color(white)("XXX")=2x^2+7x+6#

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