Question

How do you calculate `Log_sqrt(17)152`?

Answer 1

`2 (log 152/log 17)= 3.5464`, nearly.

Explanation:

Use `log_b a=log a/log b`.

`log_sqrt 17 152`

`=log 157/logsqrt 17`

#=log 167/log(17^(1/2))

`=2 (log 152/log 17)=3.5464,`nearly.