How do you calculate ${log}_{\sqrt{17}} 152$ $Log_sqrt(17)152$ ?

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Answer 1 · 2016-08-03T07:45:55

$2 (\frac{log 152}{log 17}) = 3.5464$ $2 (log 152/log 17)= 3.5464$ , nearly.

Use ${log}_{b} a = \frac{log a}{log b}$ $log_b a=log a/log b$ .

${log}_{\sqrt{17}} 152$ $log_sqrt 17 152$

$= \frac{log 157}{log \sqrt{17}}$ $=log 157/logsqrt 17$

#=log 167/log(17^(1/2))

$= 2 (\frac{log 152}{log 17}) = 3.5464,$ $=2 (log 152/log 17)=3.5464,$ nearly.

How do you calculate Log_sqrt(17)152log√17152Log_sqrt(17)152?