How do you calculate the energy of a photon of radiation with a wavelength of #6.4 times 10^-7# #m#?

Question

49820 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-08T11:38:56

The energy is #=3.11*10^-19J#

The energy of a photon is

#E=hf#

The energy is #E#

The frequency is #f#

Planck's constant is #h=6.626*10^-34Js#

But

#f=c/lambda#

The speed of light is #c=3*10^8ms^-1#

The wavelength is #lambda=6.4*10^-7m#

so,

#E=h*c/lambda#

#=6.626*10^-34*3*10^8/(6.4*10^-7)#

#=3.11*10^-19J#