Question

How do you change `(2)-(2isqrt3)` into polar coordinates?

Answer 1

`4 (cos t + i sin t)`

Explanation:

`2 = r cos t`

`-2 sqrt 3 = r sin t`

`frac {- 2 sqrt 3}{2} = tan t = - sqrt 3`

`r^2 = 2^2 + (-2 sqrt 3)^2 = 4 + 4 * 3 = 16 \Rightarrow r = 4`