How do you change the equation #2x-6y=5# from standard to point-slope and slope intercept? Algebra Forms of Linear Equations Linear Equations in Point-Slope Form 1 Answer MeneerNask Apr 3, 2015 You isolate the #y# on one side, and the rest on the other #2x-6y=5-># add #6y# and subtract #5# on both sides #2x-5=6y-># divide everything by #6# #1/3 x -5/6=y->y=1/3 x-5/6# Where #1/3# is the slope, and #-5/6# is the #y#-intercept (for #x=0#) Answer link Related questions How do you write linear equations in point slope form? What is the difference between point-slope form and slope intercept form? How do you graph equations that are written in point-slope form? How do you write an equation in point slope form when slope is #1/3# and the y- intercept is –4? How do you write the equation of a line in point slope form if the line contains the points (–2,... How do you write the equation of a line in point slope form given the line has a slope of –6 and... How do you write #y+4=\frac{-2}{3}(x+6)# in slope intercept form? How do you write #0=x+5# in slope intercept form? What is the equation written in point slope form if #f(6)=0# and #f(0)=6#? What is the equation written in point slope form if #m=25# and #f(0)=250#? See all questions in Linear Equations in Point-Slope Form Impact of this question 3200 views around the world You can reuse this answer Creative Commons License