How do you combine #2/(4-x) + 5/(x-4)#?

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Answer 1 · 2016-03-13T03:36:13

#2/(4-x)+5/(x-4)=3/(x-4)#

This is how to do it.

#2/(4-x)+5/(x-4)#

introduce a - sign both numerator and denominator of the first fraction

#(-2)/(-(4-x))+5/(x-4)#

so that

#(-2)/(-(4-x))+5/(x-4)=(-2)/(-4+x)+5/(x-4)=(-2)/(x-4)+5/(x-4)#

#=(5-2)/(x-4)#

#=3/(x-4)#

God bless...I hope the explanation is useful.