How do you combine $2/(4z^2-12z+9)-(z+1)/(2z^2-3z)$ ?

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Answer 1 · 2016-09-20T19:11:08

$(-2z^2+3z+3)/(z(2z-3)(2z-3))$

In a question involving algebraic fractions, no matter what the operation is, factorize first.

$2/(4z^2-12z+9)-(z+1)/(2z^2-3z)$

$2/((2z-3)(2z-3)) - (z+1)/(z(2z-3))" "larr$ find the LCD

= $(2z -(z+1)(2z-3))/(z(2z-3)(2z-3)) " "larr$ make equivalent fractions

$(2z -(2z^2-3z+2z-3))/(z(2z-3)(2z-3))" "larr$ simplify the numerator

$(2z -2z^2+3z-2z+3)/(z(2z-3)(2z-3))$

$(-2z^2+3z+3)/(z(2z-3)(2z-3))$

How do you combine 2/(4z^2-12z+9)-(z+1)/(2z^2-3z)2/(4z^2-12z+9)-(z+1)/(2z^2-3z)?