How do you combine #(4a-2)/(3a+12)-(a-2)/(a+4)#?
2 Answers
See a solution process below:
Explanation:
To subtract or add fractions they must be over a common denominator. We can multiply the fraction on the right by the appropriate form of
We can now subtract the numerators over the common denominator:
We can now factor the numerator and cancel common terms:
This equals
Explanation:
We can factor the denominator of the left-most expression as
#=(4a - 2 - 3(a - 2))/(3a + 12)#
#=(4a - 2 - 3a + 6)/(3a + 12)#
#=(a + 4)/(3a + 12)#
#=(a + 4)/(3(a + 4))#
#=1/3#
But don't forget that
Hopefully this helps!