Question

How do you combine `9/(b+2)+8/(b-7)`?

Answer 1

To combine `9/(b+2)+8/(b-7)`

you first need to re-write the terms with a common denominator: `(b+2)(b-7)`

`9/(b+2)+8/(b-7)`

`= (9(b-7) + 8(b+2))/((b+2)(b-7))`

`= (9b -63 +8b +16) /((b+2)(b-7))`

`= (17b-47)/(b^2-5b-14)`