How do you combine like terms in $2 a + 3 a b - 7 a b + 4 a - 9 b$ $2a + 3a b - 7a b + 4a - 9b$ ?

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Answer 1 · 2018-04-26T17:59:30

$6 a - 4 a b - 9 b$ $6a -4ab -9b$

Given: $2 a + 3 a b - 7 a b + 4 a - 9 b$ $2a + 3ab - 7ab +4a -9b$

The sign before the number always accompanies the number.

Like terms:

$2 a & 4 a : 2 a + 4 a = 6 a$ $2a " & "4a: " "2a + 4a = 6a$

$3 a b & - 7 a b : 3 a b - 7 a b = - 4 a b$ $3ab " & "-7ab: " "3ab - 7ab = -4ab$

There is only one $b$ $b$ term: $- 9 b$ $-9b$

Adding like terms gives the following result:

$2 a + 3 a b - 7 a b + 4 a - 9 b = 6 a - 4 a b - 9 b$ $2a + 3ab - 7ab +4a -9b = 6a -4ab -9b$

How do you combine like terms in 2a + 3a b - 7a b + 4a - 9b2a+3ab−7ab+4a−9b2a + 3a b - 7a b + 4a - 9b?