How do you combine #(x^2 ) / (x^2 + x- 6) - 6 / ((x+3)(x-2)) + x / (x^2 + x - 6) #?
1 Answer
May 20, 2015
The denominator of the second term upon expansion becomes
rewriting the expression:
since all terms have a common denominator the expression now becomes :
rearranging the terms present in the numerator: