How do you complete the square for $x^{2} + 6 x + 2$ $x^2 + 6x + 2$ ?

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Answer 1 · 2015-05-24T11:00:19

$x^{2} + 6 x + 2 = x^{2} + 6 x + 9 - 2 = {(x + 3)}^{2} - 2$ $x^2+6x+2 = x^2+6x+9-2 = (x+3)^2-2$

In general

$a x^{2} + b x + c = a {(x + \frac{b}{2 a})}^{2} + (c - \frac{b^{2}}{4 a})$ $ax^2+bx+c = a(x+b/(2a))^2 + (c-b^2/(4a))$

How do you complete the square for x2+6x+2x^2 + 6x + 2?