How do you complete the square to solve $4x^2 – 6x + 3 = 0$ ?

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Answer 1 · 2015-06-11T15:18:12

Solve y = 4x^2 - 6x + 3 = 0 by completing the squares

D = 36 - 48 = -12 < 0.

This equation doesn't have real roots.

How do you complete the square to solve 4x^2 – 6x + 3 = 04x^2 – 6x + 3 = 0?