How do you complete the square to solve $9 x^{2} - 12 x + 5 = 0$ $9x^2-12x+5=0$ ?

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Answer 1 · 2015-05-25T21:49:43

Halve the coefficient of x and then square it.
$\frac{12}{2} = 6$ $12/2 = 6$
$6^{2} = 36$ $6^2 = 36$
${(3 x - 6)}^{2} - 36 + 5$ $(3x-6)^2 -36 +5$

How do you complete the square to solve 9x2−12x+5=09x^2-12x+5=0?